A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is
- 0.5 Wb
- 12.5 Wb
- zero
- 2 Wb
Answer
(2) 12.5 Wb
Solution
= LI
= 5 2.5 = 12.5 Wb
Answer: (2)
A current of 2.5 A flows through a coil of inductance 5 H. The magnetic flux linked with the coil is
(2) 12.5 Wb
= LI
= 5 2.5 = 12.5 Wb
Answer: (2)
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