A coil of resistance 400 is placed in a magnetic field. If the magnetic flux (Wb) linked with the coil varies with time t (sec) as = 50t2 + 4. The current in the coil at t = 2 sec is
- 0.5 A
- 0.1 A
- 2 A
- 1 A
Answer
(1) 0.5 A
Solution
By Faraday's law, the magnitude of the induced emf is
| | = d dt = ddt(50t2 + 4) = 100t
At t = 2 s:
| | = 100 2 = 200 V
I = | |R = 200400 = 0.5 A
Answer: (1)