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Let A= bmatrix1&0&0\\0& & \\0& & bmatrix and |2A|3=221 where , Z. Then a value of is
(4) 5
|A|=1 ( 2- 2)= 2- 2
|2A|=23|A| (order 3) |2A|3=29|A|3=221
|A|3=212 2- 2=16 2= 2-16
(A): =9 2=65, not a perfect square (A) rejected
(B): =17 2=273, not a perfect square (B) rejected
(C): =3 2=-7<0 (C) rejected
(D): =5 2=9, = 3 Z (D) is correct
Answer: (4)
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