Consider the system of linear equations x+y+z=5, x+2y+ 2 z=9, x+3y+ z= , where , R. Then, which of the following statements is NOT correct?
- System is consistent if 1 and =13
- System is inconsistent if =1 and 13
- System has unique solution if 1 and 13
- System has infinite number of solutions if =1 and =13
Answer
(3) System has unique solution if 1 and 13
Solution
= vmatrix1&1&1\\1&2& 2\\1&3& vmatrix=-(2 2- -1)=-( -1)(2 +1)
=0 for =1 or =- 12
R2-R1: y+( 2-1)z=4; R3-R2: y+( - 2)z= -9
∵ for =1, - 12: 2-1= - 2 (same left sides) consistent only if -9=4, i.e. =13
(A): =13 unique ( - 12) or infinite ( =- 12) solutions (A) is correct
(B): =1, 13 y=4 and y= -9 clash (B) is correct
(C): =- 12 ( 1), 13 =0 and no solution (C) is NOT correct
(D): =1, =13 two equations only infinitely many solutions (D) is correct
Answer: (3)