An ideal gas undergoes four different processes from the same initial state as shown in the figure below. Those processes are adiabatic, isothermal, isobaric and isochoric. The curve which represents the adiabatic process among 1, 2, 3 and 4 is [figure]
- 1
- 2
- 3
- 4
Answer
(2) 2
Solution
Curve 1 is vertical (V constant) isochoric.
Curve 4 is horizontal (P constant) isobaric.
For an isothermal process, PV = constant slope dPdV = - PV
For an adiabatic process, PV = constant slope dPdV = - PV
> 1, the adiabatic curve is steeper than the isothermal curve.
Curve 2 (steeper) is adiabatic and curve 3 is isothermal.
Answer: (2)