A Carnot engine has an efficiency of 50\% when its source is at a temperature 327 . The temperature of the sink is :-
- 15
- 100
- 200
- 27
Answer
(4) 27
Solution
= 1 - T2T1, with T1 = 327 + 273 = 600 K
0.5 = 1 - T2600
T2 = 300 K = 27
Answer: (4)
A Carnot engine has an efficiency of 50\% when its source is at a temperature 327 . The temperature of the sink is :-
(4) 27
= 1 - T2T1, with T1 = 327 + 273 = 600 K
0.5 = 1 - T2600
T2 = 300 K = 27
Answer: (4)
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