A Carnot engine having an efficiency of 110 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is
- 90 J
- 99 J
- 100 J
- 1 J
Answer
(1) 90 J
Solution
For the engine, = 1 - T2T1 = 110 T2T1 = 910
Coefficient of performance of the refrigerator, = Q2W = T2T1 - T2 = 1 - = 9
Q2 = W = 9 10
= 90 J
Answer: (1)