The correct increasing order for bond angles among BF3, PF3 and ClF3 is :
- BF3 = PF3 < ClF3
- BF3 < PF3 < ClF3
- ClF3 < PF3 < BF3
- PF3 < BF3 < ClF3
Answer
(3) ClF3 < PF3 < BF3
Solution
BF3: 3 bp, 0 lp, so trigonal planar; F–B–F = 120°
PF3: 3 bp, 1 lp, so pyramidal; F–P–F ≈ 97°
ClF3: 3 bp, 2 lp (equatorial), so bent T-shape; F–Cl–F ≈ 87.5°
∵ lone pairs push the bonds closer, more lone pairs give a smaller angle
∴ ClF3 < PF3 < BF3
Answer: (3)