The number of species from the following which are paramagnetic and with bond order equal to one is . H2, He2+, O2+, N22-, O22-, F2, Ne2+, B2
Answer
1
Solution
B.O. = 12(Nb - Na); unpaired electrons from MO filling:
H2 (2e): B.O. 1, diamagnetic
He2+ (3e), Ne2+ (19e): B.O. 0.5
O2+ (15e): B.O. 2.5; N22- (16e, like O2): B.O. 2
O22-, F2 (18e): B.O. 1, diamagnetic
B2 (10e): *2s2 2px1 2py1 ⇒ B.O. 1, 2 unpaired e ⇒ paramagnetic
∴ only B2 satisfies both conditions
Answer: 1