Equilibrium

JEE Main 2025 (Online) 22nd January Morning ShiftMCQMedium📈 Topic in 21% papers+4−1

Ques. 1JEE Main 2025, 22 January (Morning Shift)

A vessel at 1000 K contains CO2 with a pressure of 0.5 atm. Some of CO2 is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm, then Kp is :

0.18 atm
0.3 atm
3 atm
1.8 atm

Answer

(4) 1.8 atm

Solution

CO2(g) + C(s) 2CO(g)

Ptotal = (0.5 - x) + 2x = 0.8 x = 0.3 atm

pCO2 = 0.2 atm, pCO = 0.6 atm

Kp = (0.6)20.2 = 1.8 atm

Answer: (4)

Keep practising — Equilibrium

Ques. 2JEE Main 2025, 22 January (Evening Shift)

The molar solubility(s) of zirconium phosphate with molecular formula ( Zr4+ )3 ( PO43- )4 is given by relation :

( Ksp5348 )1/6
( Ksp8435 )1/7
( Ksp6912 )1/7
( Ksp9612 )1/3

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All JEE Main Chemistry chapters

Physical ChemistrySome Basic Concepts of Chemistry Structure of Atom States of Matter Thermodynamics Equilibrium Redox Reactions Solutions Electrochemistry Chemical Kinetics

Inorganic ChemistryClassification of Elements and Periodicity in Properties Chemical Bonding and Molecular Structure p-Block Elements (Group 13 & 14)p-Block Elements (Group 15–18)d- and f-Block Elements Coordination Compounds

Organic ChemistryOrganic Chemistry – Some Basic Principles and Techniques Isomerism Hydrocarbons Haloalkanes and Haloarenes Alcohols, Phenols and Ethers Aldehydes, Ketones and Carboxylic Acids Amines Biomolecules Principles Related to Practical Chemistry