Equilibrium

Consider the reaction X2Y(g) X2(g) + 12Y2(g) The equation representing correct relationship between the degree of dissociation (x) of X2Y(g) with its equilibrium constant Kp is . Assume x to be very very small.

1. x = [3] KpP
2. x = [3] Kp2P
3. x = [3] 2 Kp2P
4. x = [3] 2KpP

Answer

(3) x = [3] 2 Kp2P

Solution

X2Y:1-x, X2:x, Y2: x2; for small x total moles 1

Kp= pX2 pY21/2pX2Y x ( x2 )1/2P1/2= x3/2P1/2 2

⇒ x3= 2Kp2P

Answer: (3)