Two resistances of 100 and 200 are connected in series with a battery of 4 V and negligible internal resistance. A voltmeter is used to measure voltage across 100 resistance, which gives reading as 1 V. The resistance of voltmeter must be .
Answer
200
Solution
[figure]
Voltmeter reads 1 V ⇒ 200 gets 4-1=3 V
same current in series, p.d. ∝ resistance: R = 13 200= 2003
100RV100+RV= 2003
300RV=200RV+20000 RV=200
Answer: 200