Consider the following data: Heat of formation of CO2(g) = -393.5 kJ mol-1 Heat of formation of H2O(l) = -286.0 kJ mol-1 Heat of combustion of benzene = -3267.0 kJ mol-1 The heat of formation of benzene is kJ mol-1. (Nearest integer)
Answer
48
Solution
Combustion of benzene:
C6H6(l) + 152O2(g) 6CO2(g) + 3H2O(l); c H = -3267.0 kJ mol-1
c H = [6 f H(CO2) + 3 f H(H2O)] - f H(C6H6) ( f H of O2 = 0)
-3267.0 = [6(-393.5) + 3(-286.0)] - f H(C6H6)
-3267.0 = -2361.0 - 858.0 - f H(C6H6)
-3267.0 = -3219.0 - f H(C6H6)
f H(C6H6) = +48.0 kJ mol-1
Answer: 48