There are 5 points P1, P2, P3, P4, P5 on the side AB, excluding A and B, of a triangle ABC. Similarly there are 6 points P6, P7, , P11 on the side BC and 7 points P12, P13, , P18 on the side CA of the triangle. The number of triangles, that can be formed using the points P1, P2, , P18 as vertices, is:
- 751
- 776
- 796
- 771
Answer
(1) 751
Solution
Any 3 of the 18 points form a triangle unless all 3 lie on the same side (collinear).
Number =18C3-5C3-6C3-7C3
=816-10-20-35=751
Answer: (1)