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Permutations and Combinations

JEE Main 2024 (Online) 31st January Evening ShiftMCQMedium📈 Topic in 34% papers+4−1
Ques. 1JEE Main 2024, 31 January (Evening Shift)

If for some m, n; 6Cm+2 (6Cm+1 )+6Cm+2>8C3 and n-1P3:nP4=1:8, then nPm+1+n+1Cm is equal to

  1. 380
  2. 376
  3. 372
  4. 384

Answer

(3) 372

Solution

6Cm+2 6Cm+1+6Cm+2= (6Cm+6Cm+1 )+ (6Cm+1+6Cm+2 )=7Cm+1+7Cm+2=8Cm+2

∵ nCr+nCr+1=n+1Cr+1

8Cm+2>8C3=56 and 8Cr exceeds 56 only for r=4 (8C4=70) m+2=4 m=2

n-1P3nP4= (n-1)(n-2)(n-3)n(n-1)(n-2)(n-3)= 1n= 18 n=8

8P3+9C2=336+36=372

Answer: (3)

Keep practising — Permutations and Combinations

Ques. 2JEE Main 2024, 30 January (Evening Shift)

In an examination of Mathematics paper, there are 20 questions of equal marks and the question paper is divided into three sections : A, B and C. A student is required to attempt total 15 questions taking at least 4 questions from each section. If section A has 8 questions, section B has 6 questions and section C has 6 questions, then the total number of ways a student can select 15 questions is .

Ques. 3JEE Main 2024, 29 January (Morning Shift)

All the letters of the word "GTWENTY" are written in all possible ways with or without meaning and these words are written as in a dictionary. The serial number of the word "GTWENTY" is .

Ques. 4JEE Main 2024, 29 January (Evening Shift)

Number of ways of arranging 8 identical books into 4 identical shelves where any number of shelves may remain empty is equal to

  1. 18
  2. 16
  3. 12
  4. 15
Ques. 5JEE Main 2024, 27 January (Morning Shift)

n-1Cr= (k2-8 )nCr+1 if and only if :

  1. 2 2<k<2 3
  2. 2 2<k 3
  3. 2 3<k<3 3
  4. 2 3<k 3 2
Ques. 6JEE Main 2024, 27 January (Evening Shift)

Let = (4!)!(4!)3! and = (5!)!(5!)4!. Then :

  1. and
  2. and
  3. and
  4. and

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