A particle of mass m is under the influence of the gravitational field of a body of mass M ( m). The particle is moving in a circular orbit of radius r0 with time period T0 around the mass M. Then, the particle is subjected to an additional central force, corresponding to the potential energy Vc(r) = m /r3, where is a positive constant of suitable dimensions and r is the distance from the center of the orbit. If the particle moves in the same circular orbit of radius r0 in the combined gravitational potential due to M and Vc(r), but with a new time period T1, then (T12 - T02)/T12 is given by [G is the gravitational constant.]
- 3 GMr02
- 2GMr02
- GMr02
- 2 GMr02
Answer
(1) 3 GMr02
Solution
Force from Vc: F = - dVcdr = 3m r4 (outward, repulsive).
Without it: m 02r0 = GMmr02.
With it: m 12r0 = GMmr02 - 3m r04 12 02 = 1 - 3 GMr02.
Since T 1 : T12-T02T12 = 1 - T02T12 = 1 - 12 02 = 3 GMr02
Answer: (A)