1
A geostationary satellite above the equator is orbiting around the earth at a fixed distance r1 from the center of the earth. A second satellite is orbiting in the equatorial plane in the opposite direction to the earth's rotation, at a distance r2 from the center of the earth, such that r1=1.21 r2. The time period of the second satellite as measured from the geostationary satellite is 24p hours. The value of p is
Answer
2.3 to 2.4
Solution
Kepler: T r3/2, T1=24 h.
T2= 24(1.21)3/2= 241.331 h
Opposite senses, so relative angular speed = 1+ 2= 2 24(1+1.331)
Trel= 242.331 h p=2.331 2.33
Answer: 2.33
JEE Advanced 2025 Paper 2