Consider a star of mass m2 kg revolving in a circular orbit around another star of mass m1 kg with m1 m2. The heavier star slowly acquires mass from the lighter star at a constant rate of kg/s. In this transfer process, there is no other loss of mass. If the separation between the centers of the stars is r, then its relative rate of change 1r drdt (in s-1) is given by:
- - 3 2m2
- - 2 m2
- - 2 m1
- - 3 2m1
Answer
(2) - 2 m2
Solution
Mass transfer is internal, so orbital angular momentum is conserved: L=m2 Gm1r (for m1 m2).
L= m2+ 12 m1+ 12 r=const
m2m2+ 12 m1m1+ 12 rr=0, with m2=- , m1=+
1r drdt= 2 m2- m1 + 2 m2 (since m1 m2)
The magnitude matches (B), but the separation actually increases (positive sign), so no option is exactly correct; the official key awarded marks to all.
Answer: (B) in magnitude (official: marks to all)