Let 2nd, 8th and 44th terms of a non-constant A. P. be respectively the 1st, 2nd and 3rd terms of a G. P. If the first term of the A. P. is 1, then the sum of its first 20 terms is equal to -
- 990
- 980
- 960
- 970
Answer
(4) 970
Solution
AP: a=1 ⇒ terms 1+d, 1+7d, 1+43d are in G.P.
(1+7d)2=(1+d)(1+43d)
49d2+14d=43d2+44d 6d(d-5)=0
∵ AP is non-constant, d 0 d=5
S20= 202 [2(1)+19(5) ]=10 97=970
Answer: (4)