Let , ( ) be the values of m, for which the equations x + y + z = 1, x + 2y + 4z = m and x + 4y + 10z = m2 have infinitely many solutions. Then the value of n=110(n + n ) is equal to :
- 3410
- 560
- 3080
- 440
Answer
(4) 440
Solution
=0 always; infinitely many solutions ⇒ equations consistent
R2-R1: y+3z=m-1; R3-R1: 3y+9z=m2-1
R3-3R2: 0=m2-3m+2 ⇒ m=1,2
∴ n=110(n+n2)=55+385=440
Answer: (4)