Let the system of equations x + 5y - z = 1 4x + 3y - 3z = 7 24x + y + z = , R, have infinitely many solutions. Then the number of the solutions of this system, if x, y, z are integers and satisfy 7 x + y + z 77, is :
- 4
- 5
- 3
- 6
Answer
(3) 3
Solution
For infinitely many solutions, = 0:
vmatrix 1 & 5 & -1 \ 4 & 3 & -3 \ 24 & 1 & vmatrix = (3 + 3) - 5(4 + 72) - (4 - 72) = 0
-17 - 289 = 0 = -17
The third equation must be a combination a(I) + b(II):
a + 4b = 24, 5a + 3b = 1 b = 7, a = -4 (z-coefficient: -a - 3b = -17 ✓)
= a(1) + b(7) = -4 + 49 = 45
Solve the first two equations with z = t:
x + 5y = 1 + t, 4x + 3y = 7 + 3t
y = t - 317, x = 12t + 3217
For integer y, put t = 17k + 3 (k Z):
x = 12k + 4, y = k, z = 17k + 3 (all integers)
x + y + z = 30k + 7
7 30k + 7 77 0 k 73 k = 0, 1, 2
number of integer solutions = 3
Answer: (3)