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p-Block Elements (Group 15–18) · Question 30

NEET 2016 (Phase 1)MatchingMedium📈 Topic in 12% papers+4−1
1

Match the compounds given in column I with the hybridisation and shape given in column II and mark the correct option

  1. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
  2. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
  3. (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
  4. (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)

Answer

(3) (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

Solution

(a) XeF6: 6 bond pairs + 1 lone pair (sp3d3) ⇒ distorted octahedral ⇒ (i).

(b) XeO3: 3 bond pairs + 1 lone pair (sp3) ⇒ pyramidal ⇒ (iii).

(c) XeOF4: 5 bond pairs + 1 lone pair (sp3d2) ⇒ square pyramidal ⇒ (iv).

(d) XeF4: 4 bond pairs + 2 lone pairs (sp3d2) ⇒ square planar ⇒ (ii).

∴ (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)

Answer: (3)

NEET 2016 (Phase 1)

Keep practising — p-Block Elements (Group 15–18)

2

Which is the correct statement for the given acids?

  1. Phosphinic acid is a monoprotic acid while phosphonic acid is a diprotic acid.
  2. Phosphinic acid is a diprotic acid while phosphonic acid is a monoprotic acid.
  3. Both are diprotic acids.
  4. Both are triprotic acids.
NEET 2016 (Phase 1)
3

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules?

  1. Br2 > I2 > F2 > Cl2
  2. F2 > Cl2 > Br2 > I2
  3. I2 > Br2 > Cl2 > F2
  4. Cl2 > Br2 > F2 > I2
NEET 2016 (Phase 1)
4

When copper is heated with conc. HNO3 it produces

  1. Cu(NO3)2, NO and NO2
  2. Cu(NO3)2 and N2O
  3. Cu(NO3)2 and NO2
  4. Cu(NO3)2 and NO
NEET 2016 (Phase 1)
5

Among the following the correct order of acidity is

  1. HClO2 < HClO < HClO3 < HClO4
  2. HClO4 < HClO2 < HClO < HClO3
  3. HClO3 < HClO4 < HClO2 < HClO
  4. HClO < HClO2 < HClO3 < HClO4
NEET 2016 (Phase 1)
6

Hot concentrated sulphuric acid is a moderately strong oxidizing agent. Which of the following reactions does not show oxidizing behaviour?

  1. Cu + 2H2SO4 CuSO4 + SO2 + 2H2O
  2. 3S + 2H2SO4 3SO2 + 2H2O
  3. C + 2H2SO4 CO2 + 2SO2 + 2H2O
  4. CaF2 + H2SO4 CaSO4 + 2HF
NEET 2016 (Phase 2)
7

Strong reducing behavior of H3PO2 is due to

  1. high electron gain enthalpy of phosphorus
  2. high oxidation state of phosphorus
  3. presence of two -OH groups and one P-H bond
  4. presence of one -OH group and two P-H bonds.
AIPMT 2015
8

The variation of the boiling points of the hydrogen halides is in the order HF > HI > HBr > HCl. What explains the higher boiling point of hydrogen fluoride?

  1. There is strong hydrogen bonding between HF molecules.
  2. The bond energy of HF molecules is greater than in other hydrogen halides.
  3. The effect of nuclear shielding is much reduced in fluorine which polarises the HF molecule.
  4. The electronegativity of fluorine is much higher than for other elements in the group.
AIPMT 2015
9

Which of the statements given below is incorrect?

  1. O3 molecule is bent.
  2. ONF is isoelectronic with O2N-
  3. OF2 is an oxide of fluorine.
  4. Cl2O7 is an anhydride of perchloric acid.
AIPMT 2015
10

Nitrogen dioxide and sulphur dioxide have some properties in common. Which property is shown by one of these compounds, but not by the other?

  1. Is soluble in water.
  2. Is used as a food preservative.
  3. Forms 'acid-rain'.
  4. Is a reducing agent.
AIPMT 2015 (Cancelled)
11

Acidity of diprotic acids in aqueous solutions increases in the order

  1. H2S < H2Se < H2Te
  2. H2Se < H2S < H2Te
  3. H2Te < H2S < H2Se
  4. H2Se < H2Te < H2S
AIPMT 2014

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