A transition metal 'M' among Sc, Ti, V, Cr, Mn and Fe has the highest second ionisation enthalpy. The spin-only magnetic moment value of M+ ion is BM (Nearest integer) (Given atomic number Sc : 21, Ti : 22, V : 23, Cr : 24, Mn : 25, Fe : 26)
Answer
6
Solution
Cr is [Ar]3d5 4s1, so Cr+ is [Ar]3d5 (stable half-filled).
The second electron of Cr must come out of this stable 3d5, while for the others it comes from 4s; hence Cr has the highest second ionisation enthalpy, so M = Cr.
Cr+ (3d5) has n = 5 unpaired electrons:
= n(n + 2) = 35 = 5.92 BM 6
Answer: 6