The length of the latus rectum and directrices of hyperbola with eccentricity e are 9 and x = 4 3, respectively. Let the line y - 3x + 3 = 0 touch this hyperbola at (x0, y0). If m is the product of the focal distances of the point (x0, y0), then 4e2 + m is equal to .
Answer
BONUS
Solution
Tangent y = 3x - 3 to x2a2 - y2b2 = 1: c2 = a2m2 - b2 3 = 3a2 - b2
Latus rectum: 2b2a = 9 b2 = 9a2
3a2 - 9a2 - 3 = 0 2a2 - 3a - 2 = 0 a = 2, b2 = 9
e2 = 1 + 94 = 134 directrices x = ae = 4 13, not 4 3
the given data are inconsistent: no hyperbola satisfies all the conditions
If the directrices were x = 4 13:
Tangent at (x0, y0): xx04 - yy09 = 1 x - y 3 = 1
(x0, y0) = (4, 3 3 )
m = (ex0 + a)(ex0 - a) = e2x02 - a2 = 52 - 4 = 48
4e2 + m = 13 + 48 = 61
Answer: Bonus (full marks to all who attempted)
Note: The official NTA answer key gives 61. Our faculty team finds that the given data are inconsistent, so this question should be dropped (bonus: full marks to everyone who attempted it).