A current carrying closed loop in the form of a right angle isosceles triangle ABC is placed in uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on the arm AC is [figure]
- - 2 F
- - F
- F
- 2 F
Answer
(2) - F
Solution
The magnetic field is along AB, so the force on arm AB is zero ( = 0 ).
For any closed current loop in a uniform magnetic field, the net magnetic force is zero.
FAB + FBC + FAC = 0
0 + F + FAC = 0
FAC = - F
Answer: (2)