A galvanometer has a coil of resistance 100 ohm and gives a full scale deflection for 30 mA current. If it is to work as a voltmeter of 30 volt range, the resistance required to be added will be
- 900
- 1800
- 500
- 1000
Answer
(1) 900
Solution
To convert a galvanometer into a voltmeter, a high resistance R is connected in series:
V = Ig(G + R)
R = VIg - G
R = 3030 10-3 - 100
R = 1000 - 100 = 900
Answer: (1)