A closely wound solenoid of 2000 turns and area of cross-section 1.5 10-4 m2 carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field 5 10-2 tesla making an angle of 30 with the axis of the solenoid. The torque on the solenoid will be
- 3 10-3 N m
- 1.5 10-3 N m
- 1.5 10-2 N m
- 3 10-2 N m
Answer
(3) 1.5 10-2 N m
Solution
Magnetic moment of the solenoid: m = NIA
= 2000 2.0 1.5 10-4 = 0.6 A m2
Torque: = mB
= 0.6 5 10-2 30
= 1.5 10-2 N m
Answer: (3)