Let f(t) = ( 1 - ( e t)1 - ( e t) ) dt, t > 1. If f (e /2 ) = -e /2 and f (e /4 ) = e /4, then equals
- 1 + 2
- -1 - 2 2
- -1 - 2
- -1 + 2
Answer
(3) -1 - 2
Solution
Put e t = u t = eu, dt = eu du
f = eu 1 - u1 - u du
1 - u1 - u = 1 - 2 u2 u22 2 u2 = 12 cosec2 u2 - u2
With g(u) = - u2, g'(u) = 12 cosec2 u2, so the integrand is eu [g(u) + g'(u) ]
f = eu g(u) + C = -eu u2 + C
f(t) = -t ( e t2 ) + C
f (e /2 ) = -e /2 4 + C = -e /2 + C = -e /2 C = 0
f (e /4 ) = -e /4 8 = -( 2 + 1)e /4
= -1 - 2
Answer: (3)