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Integrals · Question 21

JEE Main 2026 (Online) 24th January Morning ShiftMCQHard📈 Topic in 16% papers+4−1
1

Let f(t) = ( 1 - ( e t)1 - ( e t) ) dt, t > 1. If f (e /2 ) = -e /2 and f (e /4 ) = e /4, then equals

  1. 1 + 2
  2. -1 - 2 2
  3. -1 - 2
  4. -1 + 2

Answer

(3) -1 - 2

Solution

Put e t = u t = eu, dt = eu du

f = eu 1 - u1 - u du

1 - u1 - u = 1 - 2 u2 u22 2 u2 = 12 cosec2 u2 - u2

With g(u) = - u2, g'(u) = 12 cosec2 u2, so the integrand is eu [g(u) + g'(u) ]

f = eu g(u) + C = -eu u2 + C

f(t) = -t ( e t2 ) + C

f (e /2 ) = -e /2 4 + C = -e /2 + C = -e /2 C = 0

f (e /4 ) = -e /4 8 = -( 2 + 1)e /4

= -1 - 2

Answer: (3)

JEE Main 2026 (Online) 24th January Morning Shift

Keep practising — Integrals

2

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JEE Main 2026 (Online) 24th January Evening Shift
3

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  2. 2e + 1
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4

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  1. 3
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  3. 6
  4. 12
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5

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  1. 30
  2. 29
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6

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7

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8

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9

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10

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  1. 8
  2. 4
  3. 2
  4. 6
JEE Main 2026 (Online) 21st January Morning Shift
11

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