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Oscillations · Question 18

JEE Main 2025 (Online) 2nd April Morning ShiftMCQMedium📈 Topic in 13% papers+4−1
1

A particle is subjected to two simple harmonic motions as : x1 = 7 5t cm and x2 = 2 7 (5t + 3 )cm where x is displacement and t is time in seconds. The maximum acceleration of the particle is x 10-2 m s-2. The value of x is :

  1. 5 7
  2. 125
  3. 25 7
  4. 175

Answer

(4) 175

Solution

Same = 5 rad s-1, amplitudes A1 = 7 cm, A2 = 2 7 cm, phase difference = 3

Resultant amplitude: A2 = A12 + A22 + 2A1A2

A2 = 7 + 28 + 2( 7)(2 7) ( 12 ) = 49

A = 7 cm

amax = 2 A = 25 7 = 175 cm s-2

amax = 175 10-2 m s-2 x = 175

Answer: (4)

JEE Main 2025 (Online) 2nd April Morning Shift

Keep practising — Oscillations

2

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both (A) and (R) are true but (R) is not the correct explanation of (A).
  2. (A) is true but (R) is false.
  3. Both (A) and (R) are true and (R) is the correct explanation of (A).
  4. (A) is false but (R) is true.
JEE Main 2025 (Online) 29th January Morning Shift
3

Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the correct answer from the options given below :

  1. (A) is true but (R) is false
  2. Both (A) and (R) are true but (R) is NOT the correct explanation of (A)
  3. (A) is false but (R) is true
  4. Both (A) and (R) are true and (R) is the correct explanation of (A)
JEE Main 2025 (Online) 28th January Evening Shift

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