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Trigonometric Functions · Question 23

JEE Main 2025 (Online) 4th April Morning ShiftMCQEasy📈 Topic in 10% papers+4−1
1

If 10 4 + 15 4 = 6, then the value of 27 cosec6 + 8 6 16 8 is

  1. 25
  2. 35
  3. 15
  4. 34

Answer

(1) 25

Solution

Let 2 = t, so 2 = 1 - t:

10t2 + 15(1 - t)2 = 6

⇒ 25t2 - 30t + 9 = 0

⇒ (5t - 3)2 = 0 ⇒ t = 35

∴ 2 = 35, 2 = 25

cosec6 = ( 53 )3 = 12527, 6 = ( 52 )3 = 1258, 8 = ( 52 )4 = 62516

Required value = 27 12527 + 8 125816 62516

= 250625 = 25

Answer: (1)

JEE Main 2025 (Online) 4th April Morning Shift

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2

The number of solutions of the equation 2x + 3 x = , x [-2 , 2 ] - \ 2, 3 2 \ is:

  1. 4
  2. 5
  3. 3
  4. 6
JEE Main 2025 (Online) 3rd April Morning Shift
3

The number of solutions of the equation (4 - 3) x - 2 3 2 x = - 41 + 3, x [-2 , 5 2 ] is

  1. 4
  2. 3
  3. 6
  4. 5
JEE Main 2025 (Online) 3rd April Evening Shift
4

If [-2 , 2 ], then the number of solutions of 2 2 2 + (2 - 6) - 3 = 0, is equal to:

  1. 8
  2. 6
  3. 10
  4. 12
JEE Main 2025 (Online) 2nd April Morning Shift
5

If [- 7 6, 4 3 ], then the number of solutions of 3 cosec2 - 2( 3 - 1) cosec - 4 = 0, is equal to :

  1. 7
  2. 10
  3. 6
  4. 8
JEE Main 2025 (Online) 2nd April Evening Shift
6

If r=113 \ 1 ( 4 + (r - 1) 6 ) ( 4 + r 6 ) \ = a 3 + b, a, b Z, then a2 + b2 is equal to :

  1. 10
  2. 4
  3. 8
  4. 2
JEE Main 2025 (Online) 28th January Evening Shift

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