The net impedance of circuit (as shown in figure) will be : [figure]
- 15
- 5 5
- 25
- 10 2
Answer
(2) 5 5
Solution
XL = 2 fL = 2 50 50 10-3
XL = 5
XC = 12 fC = 12 50 103 10-6
XC = 10.1 = 10
Z = R2 + (XC - XL)2
Z = 102 + 52 = 125
Z = 5 5
Answer: (2)
The net impedance of circuit (as shown in figure) will be : [figure]
(2) 5 5
XL = 2 fL = 2 50 50 10-3
XL = 5
XC = 12 fC = 12 50 103 10-6
XC = 10.1 = 10
Z = R2 + (XC - XL)2
Z = 102 + 52 = 125
Z = 5 5
Answer: (2)
The peak voltage of the ac source is equal to
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