A series LCR circuit is connected to an ac voltage source. When L is removed from the circuit, the phase difference between current and voltage is 3. If instead C is removed from the circuit, the phase difference is again 3 between current and voltage. The power factor of the circuit is :
- 0.5
- 1.0
- -1.0
- zero
Answer
(2) 1.0
Solution
With L removed (RC circuit): 3 = XCR
With C removed (RL circuit): 3 = XLR
XL = XC (resonance)
Z = R2 + (XL - XC)2 = R
Power factor, = RZ = 1
Answer: (2)