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Moving Charges and Magnetism · Question 80

AIPMT 2004MCQEasy📈 Topic in 12% papers+4−1
1

A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 10-4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

  1. 2500 as a shunt
  2. 2450 as a shunt
  3. 2550 in series
  4. 2450 in series

Answer

(4) 2450 in series

Solution

Full-scale current: Ig = 25 4 10-4 = 10-2 A

For a voltmeter of range V: V = Ig (G + R)

R = VIg - G = 2510-2 - 50

R = 2500 - 50 = 2450 in series

Answer: (4)

AIPMT 2004

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2

To convert a galvanometer into a voltmeter one should connect a

  1. high resistance in series with galvanometer
  2. low resistance in series with galvanometer
  3. high resistance in parallel with galvanometer
  4. low resistance in parallel with galvanometer
AIPMT 2004
3

A charged particle moves through a magnetic field in a direction perpendicular to it. Then the

  1. speed of the particle remains unchanged
  2. direction of the particle remains unchanged
  3. acceleration remains unchanged
  4. velocity remains unchanged
AIPMT 2003
4

A long solenoid carrying a current produces a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is

  1. B/2
  2. B
  3. 2B
  4. 4B
AIPMT 2003
5

To convert a galvanometer into a voltmeter one should connect a

  1. high resistance in series with galvanometer
  2. low resistance in series with galvanometer
  3. high resistance in parallel with galvanometer
  4. low resistance in parallel with galvanometer.
AIPMT 2002
6

A charge q moves in a region where electric field and magnetic field both exist, then force on it is

  1. q ( v B )
  2. q E + q ( v B )
  3. q E + q ( B v )
  4. q B + q ( E v )
AIPMT 2002
7

The magnetic field of given length of wire for single turn coil at its centre is B then its value for two turns coil for the same wire is

  1. B/4
  2. B/2
  3. 4B
  4. 2B
AIPMT 2002
8

If number of turns, area and current through a coil is given by n, A and i respectively then its magnetic moment will be

  1. niA
  2. n2iA
  3. niA2
  4. ni A
AIPMT 2001
9

An electron having mass m and kinetic energy E enters a uniform magnetic field B perpendicularly, then its frequency will be

  1. eEqvB
  2. 2 meB
  3. eB2 m
  4. 2meBE
AIPMT 2001
10

In Thomson mass spectrograph, if E B, then the velocity of electron beam will be

  1. | E|| B|
  2. E B
  3. | B|| E|
  4. E2 B2
AIPMT 2001
11

The magnetic field at centre, P will be [figure]

  1. 04
  2. 0
  3. 02
  4. 4 0
AIPMT 2000

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