One mole of an ideal monatomic gas undergoes a cyclic process as shown in the figure. The total heat supplied to the gas is: [figure]
- 800 J
- 400 J
- 500 J
- 600 J
Answer
(4) 600 J
Solution
For a complete cycle, the net heat supplied to the gas equals the net work done in the cycle:
Qnet = Wnet = Area of the loop
Area = (P2 - P1)(V2 - V1) = (300 - 100) (5 - 2) = 200 3 = 600 J
Answer: (4)