A 250-turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180 against the torque is
- 4.55
- 2.3
- 1.15
- 9.1
Answer
(4) 9.1
Solution
Work done in rotating a dipole from = 0 to 180 :
W = MB( 0 - 180 ) = 2MB = 2NIAB
A = 2.1 1.25 cm2 = 2.625 10-4 m2
W = 2 250 85 10-6 2.625 10-4 0.85
9.5 10-6 J
W 9.1 (the nearest option)
Answer: (4)