An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current 'I' along the same direction as shown in figure. Magnitude of force per unit length on the middle wire 'B' is given by [figure]
- 2 0 I2 d
- 2 0 I2 d
- 0 I2 2 d
- 0 I22 d
Answer
(3) 0 I2 2 d
Solution
Parallel wires with currents in the same direction attract each other.
Force per unit length on B due to A (along BA) and due to C (along BC):
fBA = fBC = 0 I22 d
BA BC, the two forces are at 90 :
f = fBA2 + fBC2 = 2 0 I22 d
f = 0 I2 2 d
Answer: (3)