Three small identical bubbles of water having same charge on each coalesce to form a bigger bubble. Then the ratio of the potentials on one initial bubble and that on the resultant bigger bubble is :
- 1 : 32/3
- 32/3 : 1
- 1 : 31/3
- 1 : 22/3
Answer
(1) 1 : 32/3
Solution
Let each small drop have radius r and charge q; potential V1 = kqr
Volume is conserved: 43 R3 = 3 43 r3 R = 31/3r
Charge is conserved: Q = 3q
V2 = kQR = 3kq31/3r = 32/3 kqr = 32/3V1
V1 : V2 = 1 : 32/3
Answer: (1)