Consider the following reaction A + B C The time taken for A to become 1/4th of its initial concentration is twice the time taken to become 1/2 of the same. Also, when the change of concentration of B is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is .
Answer
1
Solution
For A: t1/4 = 2t1/2, i.e. the second half-life equals the first; a constant half-life means first order in A.
For B: [B] vs t is a straight line with slope −k and intercept [B]0, i.e. [B] = [B]0 - kt; this is zero order in B.
∴ Overall order = 1 + 0 = 1
Answer: 1