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Chemical Kinetics

JEE Main 2024 (Online) 8th April Morning ShiftNumericalEasy📈 Topic in 15% papers+4
Ques. 1JEE Main 2024, 8 April (Morning Shift)

Consider the following reaction A + B C The time taken for A to become 1/4th of its initial concentration is twice the time taken to become 1/2 of the same. Also, when the change of concentration of B is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is .

Answer

1

Solution

For A: t1/4 = 2t1/2, i.e. the second half-life equals the first; a constant half-life means first order in A.

For B: [B] vs t is a straight line with slope −k and intercept [B]0, i.e. [B] = [B]0 - kt; this is zero order in B.

∴ Overall order = 1 + 0 = 1

Answer: 1

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Ques. 2JEE Main 2024, 8 April (Evening Shift)

For a reaction A K1 B K2 C. If the rate of formation of B is set to be zero then the concentration of B is given by :

  1. (K1 - K2)[A]
  2. (K1 + K2)[A]
  3. K1K2[A]
  4. (K1/K2)[A]
Ques. 3JEE Main 2024, 6 April (Morning Shift)

Time required for 99.9\% completion of a first order reaction is times the time required for completion of 90\% reaction.(nearest integer)

Ques. 4JEE Main 2024, 6 April (Evening Shift)

Consider the two different first order reactions given below A + B C (Reaction 1) P Q (Reaction 2) The ratio of the half life of Reaction 1 : Reaction 2 is 5 : 2. If t1 and t2 represent the time taken to complete 2/3rd and 4/5th of Reaction 1 and Reaction 2, respectively, then the value of the ratio t1 : t2 is 10-1 (nearest integer). [Given : 10(3) = 0.477 and 10(5) = 0.699]

Ques. 5JEE Main 2024, 5 April (Morning Shift)

During kinetic study of reaction 2A + B C + D, the following results were obtained : [figure] Based on above data, overall order of the reaction is .

Ques. 6JEE Main 2024, 5 April (Evening Shift)

Consider the following single step reaction in gas phase at constant temperature. 2A(g) + B(g) C(g) The initial rate of the reaction is recorded as r1 when the reaction starts with 1.5 atm pressure of A and 0.7 atm pressure of B. After some time, the rate r2 is recorded when the pressure of C becomes 0.5 atm. The ratio r1 : r2 is 10-1. (Nearest integer)

Ques. 7JEE Main 2024, 4 April (Morning Shift)

Consider the following transformation involving first order elementary reaction in each step at constant temperature as shown below. [figure] Some details of the above reactions are listed below. [figure] If the overall rate constant of the above transformation (k) is given as k = k1k2k3 and the overall activation energy (Ea) is 400 kJ mol-1, then the value of Ea3 is kJ mol-1 (nearest integer)

Ques. 8JEE Main 2024, 4 April (Evening Shift)

Consider the following reaction, the rate expression of which is given below A + B C rate = k[A]1/2[B]1/2 The reaction is initiated by taking 1 M concentration of A and B each. If the rate constant (k) is 4.6 10-2 s-1, then the time taken for A to become 0.1 M is sec. (nearest integer)

Ques. 9JEE Main 2024, 1 February (Morning Shift)

The ratio of 14C12C in a piece of wood is 18 part that of atmosphere. If half life of 14C is 5730 years, the age of wood sample is years.

Ques. 10JEE Main 2024, 1 February (Evening Shift)

The following data were obtained during the first order thermal decomposition of a gas A at constant volume : A(g) 2B(g) + C(g) [figure] The rate constant of the reaction is 10-2 s-1 (nearest integer)

Ques. 11JEE Main 2024, 31 January (Morning Shift)

Integrated rate law equation for a first order gas phase reaction is given by (where Pi is initial pressure and Pt is total pressure at time t)

  1. k = 2.303t Pi(2Pi - Pt)
  2. k = 2.303t (2Pi - Pt)Pi
  3. k = 2.303t Pi(2Pi - Pt)
  4. k = 2.303t 2Pi(2Pi - Pt)

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