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Chemical Kinetics

JEE Main 2024 (Online) 5th April Evening ShiftNumericalMedium📈 Topic in 15% papers+4
Ques. 1JEE Main 2024, 5 April (Evening Shift)

Consider the following single step reaction in gas phase at constant temperature. 2A(g) + B(g) C(g) The initial rate of the reaction is recorded as r1 when the reaction starts with 1.5 atm pressure of A and 0.7 atm pressure of B. After some time, the rate r2 is recorded when the pressure of C becomes 0.5 atm. The ratio r1 : r2 is 10-1. (Nearest integer)

Answer

315

Solution

Single step (elementary) ⇒ rate = k pA2 pB

pC = 0.5 atm ⇒ A used = 2 × 0.5 = 1.0 atm, B used = 0.5 atm

⇒ pA = 1.5 − 1.0 = 0.5 atm, pB = 0.7 − 0.5 = 0.2 atm

r1r2 = (1.5)2(0.7)(0.5)2(0.2) = 1.5750.05

= 31.5 = 315 10-1

Answer: 315

Keep practising — Chemical Kinetics

Ques. 2JEE Main 2024, 4 April (Morning Shift)

Consider the following transformation involving first order elementary reaction in each step at constant temperature as shown below. [figure] Some details of the above reactions are listed below. [figure] If the overall rate constant of the above transformation (k) is given as k = k1k2k3 and the overall activation energy (Ea) is 400 kJ mol-1, then the value of Ea3 is kJ mol-1 (nearest integer)

Ques. 3JEE Main 2024, 4 April (Evening Shift)

Consider the following reaction, the rate expression of which is given below A + B C rate = k[A]1/2[B]1/2 The reaction is initiated by taking 1 M concentration of A and B each. If the rate constant (k) is 4.6 10-2 s-1, then the time taken for A to become 0.1 M is sec. (nearest integer)

Ques. 4JEE Main 2024, 1 February (Morning Shift)

The ratio of 14C12C in a piece of wood is 18 part that of atmosphere. If half life of 14C is 5730 years, the age of wood sample is years.

Ques. 5JEE Main 2024, 1 February (Evening Shift)

The following data were obtained during the first order thermal decomposition of a gas A at constant volume : A(g) 2B(g) + C(g) [figure] The rate constant of the reaction is 10-2 s-1 (nearest integer)

Ques. 6JEE Main 2024, 31 January (Morning Shift)

Integrated rate law equation for a first order gas phase reaction is given by (where Pi is initial pressure and Pt is total pressure at time t)

  1. k = 2.303t Pi(2Pi - Pt)
  2. k = 2.303t (2Pi - Pt)Pi
  3. k = 2.303t Pi(2Pi - Pt)
  4. k = 2.303t 2Pi(2Pi - Pt)
Ques. 7JEE Main 2024, 31 January (Evening Shift)

r = k[A] for a reaction, 50% of A is decomposed in 120 minutes. The time taken for 90% decomposition of A is minutes.

Ques. 8JEE Main 2024, 30 January (Morning Shift)

The rate of a first order reaction is 0.04 mol L-1 s-1 at 10 minutes and 0.03 mol L-1 s-1 at 20 minutes after initiation. Half life of the reaction is minutes. (Given 2 = 0.3010, 3 = 0.4771)

Ques. 9JEE Main 2024, 30 January (Evening Shift)

NO2 required for a reaction is produced by decomposition of N2O5 in CCl4 as by equation 2N2O5(g) 4NO2(g) + O2(g) The initial concentration of N2O5 is 3 mol L-1 and it is 2.75 mol L-1 after 30 minutes. The rate of formation of NO2 is x 10-3 mol L-1 min-1, value of x is . (nearest integer)

Ques. 10JEE Main 2024, 29 January (Morning Shift)

For a reaction taking place in three steps at same temperature, overall rate constant K = K1 K2K3. If Ea1, Ea2 and Ea3 are 40, 50 and 60 kJ/mol respectively, the overall Ea is kJ/mol.

Ques. 11JEE Main 2024, 29 January (Evening Shift)

The half-life of radioisotope bromine - 82 is 36 hours. The fraction which remains after one day is 10-2. (Given antilog 0.2006 = 1.587)

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