Chemical Kinetics · Question 73

AIPMT 2001MCQEasy📈 Topic in 38% papers+4−1

A human body required 0.01 m activity of radioactive substance after 24 hours. Half life of radioactive substance is 6 hours. Then injection of maximum activity of radioactive substance that can be injected is

0.08
0.04
0.16
0.32

Answer

(3) 0.16

Solution

Radioactive decay is a first order process.

Number of half-lives, n = 24 h6 h = 4

A = A02n

A0 = A 2n

= 0.01 24

= 0.16

Answer: (3)

AIPMT 2001

Keep practising — Chemical Kinetics

For the reaction 6H+ + BrO3- + 5Br- 3Br2 + 3H2O which of the following relation correctly represents the consumption and formation of products.

d[Br2]dt = - 35 d[Br-]dt
d[Br2]dt = 35 d[Br-]dt
d[Br2]dt = - 53 d[Br-]dt
d[Br2]dt = 53 d[Br-]dt

AIPMT 2000

A 300 g radioactive sample has a half-life of 3 hours. After 18 hours, the remaining quantity is

4.68 g
2.34 g
3.34 g
9.37 g

AIPMT 2000

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