1
Percentage of Se in peroxidase anhydrous enzyme is 0.5\% by weight (at. wt. = 78.4), then the minimum molecular weight of peroxidase anhydrous enzyme is
- 1.568 104
- 1.568 103
- 15.68
- 2.136 104
Answer
(1) 1.568 104
Solution
For the minimum molecular weight, one molecule of the enzyme contains at least one Se atom.
∴ 0.5\% of the molecular weight = 78.4
⇒ 0.5100 M = 78.4
⇒ M = 78.4 1000.5
= 15680
= 1.568 104
Answer: (1)
AIPMT 2001