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Some Basic Concepts of Chemistry · Question 47

AIPMT 2002MCQEasy📈 Topic in 25% papers+4−1
1

2.5 litre of 1 M NaOH solution is mixed with another 3 litre of 0.5 M NaOH solution. Then find out molarity of resultant solution.

  1. 0.80 M
  2. 1.0 M
  3. 0.73 M
  4. 0.50 M

Answer

(3) 0.73 M

Solution

Moles of NaOH = M1V1 + M2V2

= (1 2.5) + (0.5 3) = 2.5 + 1.5 = 4.0 mol

Total volume = 2.5 + 3 = 5.5 L

∴ Molarity = 4.05.5 = 0.727 0.73 M

Answer: (3)

AIPMT 2002

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2

Percentage of Se in peroxidase anhydrous enzyme is 0.5\% by weight (at. wt. = 78.4), then the minimum molecular weight of peroxidase anhydrous enzyme is

  1. 1.568 104
  2. 1.568 103
  3. 15.68
  4. 2.136 104
AIPMT 2001
3

Molarity of liquid HCl, if density of solution is 1.17 g/cc, is

  1. 36.5
  2. 18.25
  3. 32.05
  4. 42.10
AIPMT 2001
4

Specific volume of cylindrical virus particle is 6.02 10-2 cc/g whose radius and length are 7 A and 10 A respectively. If NA = 6.02 1023, find molecular weight of virus.

  1. 15.4 kg/mol
  2. 1.54 104 kg/mol
  3. 3.08 104 kg/mol
  4. 3.08 103 kg/mol
AIPMT 2001
5

Volume of CO2 obtained by the complete decomposition of 9.85 g of BaCO3 is

  1. 2.24 L
  2. 1.118 L
  3. 0.84 L
  4. 0.56 L
AIPMT 2000

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