Let A and B be the two points of intersection of the line y + 5 = 0 and the mirror image of the parabola y2 = 4x with respect to the line x + y + 4 = 0. If d denotes the distance between A and B, and a denotes the area of SAB, where S is the focus of the parabola y2 = 4x, then the value of (a + d) is .
Answer
14
Solution
Image of a point (h, k) in x + y + 4 = 0:
x - h1 = y - k1 = -2(h + k + 4)2
(x, y) = (-k - 4, -h - 4)
So (x, y) lies on the image curve when (-y - 4, -x - 4) lies on y2 = 4x:
(-x - 4)2 = 4(-y - 4)
(x + 4)2 = -4(y + 4) (mirror image)
Put y = -5: (x + 4)2 = 4 x = -2 or x = -6
A(−2, −5), B(−6, −5) d = 4
Focus of y2 = 4x: S(1, 0); its distance from AB (y = -5) = 5
a = 12 4 5 = 10
a + d = 10 + 4 = 14
Answer: 14