A parallel beam of light travelling in air (refractive index 1.0) is incident on a convex spherical glass surface of radius of curvature 50 cm. Refractive index of glass is 1.5. The rays converge to a point at a distance x cm from the centre of curvature of the spherical surface. The value of x is cm.
Answer
100
Solution
Refraction at a spherical surface: 2v - 1u = 2 - 1R
Here 1 = 1.0, 2 = 1.5, u = - (parallel beam), R = +50 cm
1.5v - 0 = 1.5 - 1.050
1.5v = 1100
v = 150 cm from the pole (inside the glass)
The centre of curvature is 50 cm from the pole on the same side.
x = 150 - 50 = 100 cm
Answer: 100