The equivalent resistance of the infinite network given below is : [figure]
- (1 + 5 )
- 2
- (1 + 2 )
- (1 + 3 )
Answer
(4) (1 + 3 )
Solution
Let the equivalent resistance of the infinite network be R. Removing the first section (two 1 in series and one 1 across) leaves the same infinite network R.
The first vertical 1 is in parallel with R, and this combination is in series with the two horizontal 1 resistors:
R = 1 + 1 + 1 R1 + R
R(1 + R) = 2(1 + R) + R
R2 - 2R - 2 = 0
R = 2 4 + 82 = 1 3
Resistance cannot be negative R = (1 + 3 )
Answer: (4)