If the locus of the point, whose distances from the point (2, 1) and (1, 3) are in the ratio 5 : 4, is ax2 + by2 + cxy + dx + ey + 170 = 0, then the value of a2 + 2b + 3c + 4d + e is equal to :
- 37
- -27
- 437
- 5
Answer
(1) 37
Solution
Let P(x, y), A(2, 1), B(1, 3): PAPB = 54 16 PA2 = 25 PB2
16 [(x - 2)2 + (y - 1)2 ] = 25 [(x - 1)2 + (y - 3)2 ]
16x2 + 16y2 - 64x - 32y + 80
= 25x2 + 25y2 - 50x - 150y + 250
9x2 + 9y2 + 14x - 118y + 170 = 0 (constant term is 170, as given)
a = b = 9, c = 0, d = 14, e = -118
a2 + 2b + 3c + 4d + e = 81 + 18 + 0 + 56 - 118 = 37
Answer: (1)