Let , , , Z and let A( , ), B(1,0), C( , ) and D(1,2) be the vertices of a parallelogram ABCD. If AB= 10 and the points A and C lie on the line 3y=2x+1, then 2( + + + ) is equal to
- 8
- 5
- 12
- 10
Answer
(1) 8
Solution
[figure]
∵ diagonals of a parallelogram bisect each other: mid-point of AC = mid-point of BD = E(1, 1)
+ 2=1 and + 2=1
+ =2, + =2
2( + + + )=2(2+2)=8
(With AB= 10 and A on the line: A(−2, − 1), C(4, 3) — integers, as required.)
Answer: (1)