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Binomial Theorem · Question 26

JEE Main 2025 (Online) 3rd April Morning ShiftMCQEasy📈 Topic in 19% papers+4−1
1

The sum of all rational terms in the expansion of (2+ 3)8 is :

  1. 16923
  2. 18817
  3. 3763
  4. 33845

Answer

(2) 18817

Solution

Tr+1 = 8Cr 28-r( 3)r is rational only for even r.

sum of rational terms = (2+ 3)8 + (2- 3)82

(2+ 3)2 = 7 + 4 3

(2+ 3)4 = (7+4 3)2 = 97 + 56 3

(2+ 3)8 = (97+56 3)2 = 9409 + 9408 + 10864 3

= 18817 + 10864 3

Similarly, (2- 3)8 = 18817 - 10864 3

required sum = 2 188172 = 18817

Answer: (2)

JEE Main 2025 (Online) 3rd April Morning Shift

Keep practising — Binomial Theorem

2

If r=19 ( r+32r ) 9Cr = ( 32 )9 - , , N, then ( + )2 is equal to

  1. 27
  2. 81
  3. 18
  4. 9
JEE Main 2025 (Online) 3rd April Morning Shift
3

Let (1 + x + x2 )10 = a0 + a1x + a2x2 + + a20x20. If (a1 + a3 + a5 + + a19) - 11a2 = 121k, then k is equal to .

JEE Main 2025 (Online) 3rd April Evening Shift
4

The term independent of x in the expansion of ( (x + 1)(x2/3 + 1 - x1/3) - (x - 1)(x - x1/2) )10, x > 1, is :

  1. 240
  2. 120
  3. 150
  4. 210
JEE Main 2025 (Online) 2nd April Morning Shift
5

If r=010 ( 10r+1 - 110r ) 11Cr+1 = 11 - 11111010, then is equal to :

  1. 11
  2. 20
  3. 24
  4. 15
JEE Main 2025 (Online) 2nd April Evening Shift
6

The least value of n for which the number of integral terms in the Binomial expansion of ( [3]7 + [12]11)n is 183, is :

  1. 2184
  2. 2172
  3. 2196
  4. 2148
JEE Main 2025 (Online) 29th January Morning Shift
7

If = 1 + r=16(-3)r-1 12C2r-1, then the distance of the point (12, 3) from the line x - 3y + 1 = 0 is .

JEE Main 2025 (Online) 28th January Morning Shift
8

Let the coefficients of three consecutive terms Tr, Tr+1 and Tr+2 in the binomial expansion of (a + b)12 be in a G.P. and let p be the number of all possible values of r. Let q be the sum of all rational terms in the binomial expansion of ( [4]3 + [3]4)12. Then p + q is equal to:

  1. 295
  2. 283
  3. 299
  4. 287
JEE Main 2025 (Online) 28th January Evening Shift

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