A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 μF capacitor. The rate of change of potential difference across the plates of the capacitor is nearly 106 V/s. The value of is .
- 0.58
- 0.67
- 0.82
- 0.75
Answer
(2) 0.67
Solution
Id= 0 d Edt= 0A ddt ( Vd )=C dVdt
⇒ dVdt= IdC= 4.06 10-6 V/s
⇒ dVdt=0.67 106 V/s
∴ 0.67
Answer: (2)