Let y = y(x) be the solution curve of the differential equation y dydx + 2x y = x3 y, y(1) = 0. Then y( 3) is equal to:
- 6
- 12
- 3
- 4
Answer
(4) 4
Solution
Divide by y: 2 y dydx + 2x y = x3
Put y = t dtdx + 2xt = x3 (linear)
I.F. = e 2x dx = ex2
t ex2 = x3ex2dx = 12(x2 - 1)ex2 + C (put x2 = u, then by parts)
y(1) = 0: 0 = 0 + C C = 0
y = x2 - 12
at x = 3: y = 1 y( 3) = 4
Answer: (4)